Centripetal Force Homework: Solving for F with F = ma

Click For Summary
SUMMARY

The discussion focuses on calculating centripetal force using the formula F = (mass)(angular speed squared)(average radius). The user initially calculated a centripetal force of 2,270,217 with incorrect unit conversions. After converting grams to kilograms and revolutions per second to radians per second, the corrected force calculation yielded approximately 890.62 N. The final consensus confirms that the calculated force is reasonable for a classroom experiment involving a motor-driven rotator.

PREREQUISITES
  • Understanding of centripetal force and its formula
  • Knowledge of unit conversions (grams to kilograms, centimeters to meters)
  • Familiarity with angular speed and its calculation
  • Basic physics concepts related to rotational motion
NEXT STEPS
  • Study the derivation and application of the centripetal force formula
  • Learn about unit conversion techniques in physics
  • Explore angular velocity and its relationship with linear velocity
  • Investigate practical applications of centripetal force in engineering
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone involved in laboratory experiments related to rotational motion and centripetal force calculations.

jensson
Messages
25
Reaction score
0

Homework Statement


I did an expirement in my physics lab on centripetal force. I'm doing the calculations and right now I am calculating the centripetal force using equation: F= (mass)(angular speed squared)(average radius). My answers are coming out to be huge numbers.

ex: (148.8g)(52.70 rev/s)^2(5.494 cm) = 2270217

I'm not even sure what units this converts too.

If I convert g to kilegrams and revolutions/second times 2pi (in radians) then convert cm to meters I get:

(0.1488 kg) (331^2)(0.05494 m ) = 895.7 N

but this is too big as well. what am I doing wrong??
 
Last edited:
Physics news on Phys.org
You need the angular speed in the formula. How is it defined? ehild
 
the equation for angular speed we're using is 2pi (n)/elapsed time

n is revolutions

I think I need to convert this to m/s?
 
Last edited:
is 896.2 N reasonable?
 
jensson said:
is 896.2 N reasonable?

almost... It is 890.62 N. One zero is missing.

ehild
 
can you please show me how you got that? because when I put

(0.1488) (331.1^2) (0.05494) that comes out to 896.2 N
 
You are right, I misread something on my calculator.

ehild
 
that seems like a lot of Newtons! This was an experiment in class with a little motor driven rotator.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
Replies
8
Views
4K
  • · Replies 10 ·
Replies
10
Views
8K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K