Centripetal force throughout a vertical circle

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SUMMARY

The centripetal force in vertical circular motion is greatest at the bottom of the circle, contrary to the claim that it is greatest at the top. This conclusion is based on the formula for centripetal force, Fc = mv²/r, where v represents velocity and r is the radius of the circular path. The discussion highlights the importance of considering the effects of gravity and varying velocity in determining the correct position of maximum centripetal force. Misunderstandings arise when the problem lacks clarity regarding the conditions of motion, such as whether speed is constant or influenced by gravitational forces.

PREREQUISITES
  • Understanding of centripetal force and its formula, Fc = mv²/r
  • Knowledge of vertical circular motion dynamics
  • Familiarity with the concepts of tension and gravitational force
  • Basic principles of physics related to acceleration and velocity
NEXT STEPS
  • Study the effects of gravitational force on circular motion
  • Learn about the relationship between tension and centripetal force in varying speed scenarios
  • Explore problems involving centripetal acceleration in vertical circles
  • Review physics concepts related to forces in circular motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify common misconceptions about centripetal force in vertical circles.

Matthew_B
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Homework Statement


In what position in vertical circular motion is the centripetal force the greatest?
Top, Bottom, Left, or Right

Homework Equations


Can someone explain how Fc is greatest at the top?

The Attempt at a Solution


I had reasoned that since centripetal acceleration which I will assign to a is equal to v^2/r and as a result of the velocity being greatest at the bottom the centripetal acceleration (a) will also be the greatest at the bottom
Since the formula for centripetal force is Fc= ma and the mass remains constant I said that Fc will be the greatest where the centripetal acceleration (a) will be the greatest which is the bottom.
When I received my test back I was told that the centripetal force is greatest at the top rather than the bottom can someone please explain?
 
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The question is ill posed as it is not stated what velocity the circular motion has. If it is just subject to gravity and a constraining force, the correct answer is at the bottom.

One could also ask where the constraining force is the greatest (with constant speed or with speed given by motion in a gravitational field - in both cases the answer is at the bottom).
 
Orodruin said:
The question is ill posed as it is not stated what velocity the circular motion has. If it is just subject to gravity and a constraining force, the correct answer is at the bottom.

One could also ask where the constraining force is the greatest (with constant speed or with speed given by motion in a gravitational field - in both cases the answer is at the bottom).
The problem from the test had no mention of gravity or the speed at any of the given points, however I assumed that gravity is present and the velocity is changing since the that is the type of problems we have covered in my class. Do you think then that it was indeed a problem with the key? Thank you for responding to my post also.
 
Matthew_B said:
The problem from the test had no mention of gravity or the speed at any of the given points, however I assumed that gravity is present and the velocity is changing since the that is the type of problems we have covered in my class. Do you think then that it was indeed a problem with the key? Thank you for responding to my post also.

I wouldn't worry about it. Whoever set the test probably got their calculations mixed up.
 
My point is, regardless of whatever reasonable assumption you make about the velocity, the centripetal force will be greater at the bottom. The answer provided by your teacher is then simply wrong.
 
Orodruin said:
My point is, regardless of whatever reasonable assumption you make about the velocity, the centripetal force will be greater at the bottom. The answer provided by your teacher is then simply wrong.
Aright thanks for the reply
 
Hang on a moment. I think you are confusing the centripetal force with the tension in the string. The centripetal force is always constant. The tension in the string will vary but not the centripetal force.

The centripetal force Fc is always mv^2/r that's made up of the vector sum of the tension in the string and gravity.
 
Last edited:
CWatters said:
Hang on a moment. I think you are confusing the centripetal force with the tension in the string. The centripetal force is always constant. The tension in the string will vary but not the centripetal force.

The centripetal force Fc is always mv^2/r that's made up of the vector sum of the tension in the string and gravity.
He is not confusing them. You are making the assumption that the motion is with constant speed, which clearly the OP does not.
 
  • #10
Orodruin said:
He is not confusing them. You are making the assumption that the motion is with constant speed, which clearly the OP does not.
You're right I missed that.
 

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