Centripital force - did i do it correctly?

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Homework Help Overview

The discussion revolves around a physics problem involving centripetal force in the context of an amusement park ride called The Roundup. The scenario describes a rotating ring with a specified diameter and the forces acting on a rider at different points in the ride.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the calculation of centripetal force and the effects of forces acting on a rider at the top and bottom of the ride. Questions arise regarding the correct application of Newton's laws, the identification of forces, and the interpretation of acceleration in the context of the problem.

Discussion Status

The discussion is active, with participants attempting to clarify their understanding of the forces involved and how to set up equations correctly. Some guidance has been provided regarding the direction of forces and the implications of normal force at different positions in the ride.

Contextual Notes

Participants express confusion about the relationship between centripetal acceleration and the forces acting on the rider, as well as the implications of normal force becoming zero at certain conditions. There is also mention of the need to adhere to sign conventions in their calculations.

  • #31
yay! thank you so much!
 
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  • #32
oh no , am i doing something wrong.

don't the m's cancel out on both sides. so you get g=V^2 / r
so 9.8= v^2 / 9.5
so v = 9.65
 
  • #33
Good! Now use that to find the the corresponding period.

(The mass canceling just means that the answer does not depend on the mass.)
 
  • #34
i'm sorry i don't know how to do that? isn't a period just 2xpixr or am i thinking of the wrong thing
 
  • #35
The period is the time it takes to go around one complete spin. You have the speed; the distance is one circumference.
 
  • #36
i'm sorry i still do not understand. so i need to multiply the speed (9.65) by the distance (2PiR) ?
 
  • #37
You should know this: Distance = speed X time.
 
  • #38
ooh i see what you are saying. I'm sorry i should have realized that.
 

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