Centripital force - did i do it correctly?

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The discussion revolves around calculating the centripetal force acting on a rider in an amusement park ride called The Roundup. The rider's mass is 59 kg, and the ring has a diameter of 19 m, leading to a radius of 9.5 m. The calculations involve determining the speed of the ring and the forces acting on the rider at both the top and bottom of the ride, with emphasis on the roles of normal force and gravitational force. The conversation highlights the importance of understanding the direction of forces and how they change depending on the rider's position. The final question addresses the minimum rotation period required to prevent riders from falling off at the top, emphasizing the relationship between speed, radius, and gravitational force.
  • #31
yay! thank you so much!
 
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  • #32
oh no , am i doing something wrong.

don't the m's cancel out on both sides. so you get g=V^2 / r
so 9.8= v^2 / 9.5
so v = 9.65
 
  • #33
Good! Now use that to find the the corresponding period.

(The mass canceling just means that the answer does not depend on the mass.)
 
  • #34
i'm sorry i don't know how to do that? isn't a period just 2xpixr or am i thinking of the wrong thing
 
  • #35
The period is the time it takes to go around one complete spin. You have the speed; the distance is one circumference.
 
  • #36
i'm sorry i still do not understand. so i need to multiply the speed (9.65) by the distance (2PiR) ?
 
  • #37
You should know this: Distance = speed X time.
 
  • #38
ooh i see what you are saying. I'm sorry i should have realized that.
 

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