- #1

jonjacson

- 453

- 38

d

^{2}y/dx

^{2}

And we want to consider x as function of y instead of y as function of x.

I understand this equality:

dy/dx = 1/ (dx/dy)

But for the second order this equality is provided:

d

^{2}y/dx

^{2}=- d

^{2}x/dy

^{2}/ (dx/dy)

^{3}

Does anybody understand where is it coming from? The cubic term in the denominator looks quite strange, I don't know how to understand that equation.

ANy help is welcome.