# Chain Rule and Partial Derivatives

## Homework Statement

Here is the problem:
http://dl.dropbox.com/u/64325990/MATH%20253/help.PNG [Broken]

## The Attempt at a Solution

http://dl.dropbox.com/u/64325990/Photobook/Photo%202012-05-24%209%2037%2028%20PM.jpg [Broken]

This seems to be wrong... Since I have fx and fy which I cannot cancel out. Why is this wrong?

I guess it can only cancel is fx = fy but how do I prove that? We don't even know what f is.

#### Attachments

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## Answers and Replies

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Mark44
Mentor
You're more likely to get help if you don't make people open different windows to see the problem and what you did. Speaking for myself only, if you aren't motivated enough to at least try to make it easier for me to help, then I'm likewise not motivated enough to provide any help.

You're more likely to get help if you don't make people open different windows to see the problem and what you did. Speaking for myself only, if you aren't motivated enough to at least try to make it easier for me to help, then I'm likewise not motivated enough to provide any help.
Oh I'm sorry I just thought it would be easier for the people who are not logged onto their physicsforum account. That way they can see it too. I will upload them to the site as well then...

Edit: I tried to upload the other picture but apparently it was too large. Anyone know how to decrease the image size? I don't have photoshop.

Edit: Ok so turns out you can insert images... But the other image is once again too large. Next time I will edit it on my iphone before uploading it to Dropbox.

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Dick
Homework Helper
The partial derivative with respect to x of f(x^2-y^2) is just f'(x^2-y^2)*2x. There's really only one way to take a derivative of f.

The partial derivative with respect to x of f(x^2-y^2) is just f'(x^2-y^2)*2x. There's really only one way to take a derivative of f.
Thanks but aren't fx and fy different? Since you can take the derivative of f with respect to both x and y. I reuploaded a new attempt I made and it shoes that they are not equal unless fx = fy. But I don't think fx = fy.

Dick