Chain Rule and 'The Mob'....Pretty darn good explanation

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SUMMARY

The forum discussion centers on a YouTube video where a presenter explains the calculus chain rule using an analogy from a popular mob movie. While the analogy is engaging, the presenter incorrectly states the formula for the derivative of a composite function. The correct expression is given as $h'(c) = (g \circ f)'(c) = g'(f(c))\cdot f'(c)$, while the video inaccurately presents the denominator in the limit. Additionally, it is emphasized that the function f must be differentiable, which implies continuity, a crucial aspect that was overlooked in the explanation.

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This guy relates the calculus chain rule to a popular mob movie. You should really check it out. This is one of the newer videos but people like the way this guy explains things. Here is the link:

Ghetto Dude Relates Calculus Chain Rule To "THE MOB" - YouTube
 
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his analogy is apt, but some of his math is wrong.

the formula:

$h'(c) = (g \circ f)'(c) = g'(f(c))\cdot f'(c)$

is correctly expressed as:

$$\left(\lim_{f(x) \to f(c)} \dfrac{g(f(x)) - g(f(c))}{f(x) - f(c)}\right)\left(\lim_{x \to c} \dfrac{f(x) - f(c)}{x - c}\right)$$

whereas in the video he writes:

$$h'(c) = \lim_{x \to c} \dfrac{g(f(x)) - g(f(c))}{x - c} \cdot \dfrac{f(x) - f(c)}{x - c}$$

that is he has the denominator wrong in the first factor, so we can't "cancel" the f(x) - f(c) term to obtain:

$$h'(c) = \lim_{x \to c} \dfrac{g(f(x)) - g(f(c))}{x - c} = \lim_{x \to c} \dfrac{h(x) - h(c)}{x - c}$$

an important point is also glossed over:

f has to be differentiable, and differentiable means continuous, so f(x)-->f(c) as x-->c. this is KEY.

i give him credit for his vivid analogy, but algebra counts, too.
 

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