Using Chain Rule to Solve Questions - A Step-by-Step Guide

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SUMMARY

This discussion focuses on applying the chain rule in multivariable calculus to solve specific problems involving functions of multiple variables. The chain rule is defined as $\frac{\partial f}{\partial t}= f_x\frac{\partial x}{\partial t}+ f_y\frac{\partial y}{\partial t}+ f_z\frac{\partial z}{\partial t}$ and $\frac{\partial f}{\partial s}= f_x\frac{\partial x}{\partial s}+ f_y\frac{\partial y}{\partial s}+ f_z\frac{\partial z}{\partial s}$. Participants worked through examples such as $f(x, y, z)= xyz^{10}$ and $f= x^{10}+ y^{11}+ z$, detailing the necessary partial derivatives and substitutions. The discussion highlights common pitfalls in applying the chain rule and emphasizes the importance of correctly identifying each variable's dependency.

PREREQUISITES
  • Understanding of multivariable calculus concepts
  • Familiarity with partial derivatives
  • Knowledge of the chain rule in calculus
  • Basic algebraic manipulation skills
NEXT STEPS
  • Practice solving multivariable calculus problems using the chain rule
  • Study the derivation and applications of the chain rule in different contexts
  • Learn about implicit differentiation and its relationship to the chain rule
  • Explore advanced topics in multivariable calculus, such as Jacobians and Hessians
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Students and professionals in mathematics, engineering, and physics who need to apply the chain rule in multivariable calculus problems. This discussion is particularly beneficial for those preparing for exams or working on complex calculus assignments.

EconometricAli
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Hey everyone, could anyone help me figure out how to use chain rule to solve these questions in the attachments below?
 

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Okay your second picture gives the "chain rule":
If f is a function of x, y, and z and x, y, and z are functions of the variables, s and t, then f is a function of s and t and $\frac{\partial f}{\partial t}= f_x\frac{\partial x}{\partial t}+ f_y\frac{\partial y}{\partial t}+ f_z\frac{\partial z}{\partial t}$ and $\frac{\partial f}{\partial s}= f_x\frac{\partial x}{\partial s}+ f_y\frac{\partial y}{\partial s}+ f_z\frac{\partial z}{\partial s}$.
Great!

Now, in the first problem, $f(x, y, z)= xyz^{10}$, $x= t^3$, $y= ln(s^2\sqrt{t})$, and $z= e^{st}$.

The first thing I would do is write $y= 2(1/2)ln(st)= ln(st)$.

Now $f_x= yz^{10}$ and $\frac{\partial x}{\partial t}= 3t^2$ so $f_x\frac{\partial x}{\partial t}= 3t^2yz^{10}$. If you want to reduce that to s and t only, replace y with $ln(st)$ and z with $e^{st}$ to get $f_x\frac{\partial x}{\partial t}= 3t^3ln(sy)e^{10st}$.

$f_y= xz^{10}$ and $\frac{\partial y}{\partial t}= \frac{s}{t}$1 so $f_y\frac{\partial y}{\partial t}= xz^{10}\frac{s}{t}=\frac{st^3e^{10st}}{t}= st^2e^{10t}$.

$f_z= 10xyz^9$ and $\frac{\partial z}{\partial t}=se^{st}$ so $f_z\frac{\partial z}{\partial x}= 10xyz^9(se^{st})= 10(t^3)ln(st)e^{9st}(se^{st})= 90st^3ln(st)e^{10st}$.

$\frac{\partial f}{\partial t}$ is the sum of those.

$\frac{\partial f}{\partial s}$ is done the same way but with $\frac{\partial x}{\partial s}$, $\frac{\partial y}{\partial s}$, and $\frac{\partial z}{\partial s}$.
 
Country Boy said:
The first thing I would do is write $y=2(1/2)ln(st)=ln(st)$
$y = \ln(s^2 \cdot \sqrt{t}) = 2\ln(s) + \dfrac{1}{2}\ln(t)$
 
One of these days I really need to learn Math!
 
Thank you for the response but I'm lost in part b. The portion where fx (dx/dt) for x^10+y^11+z^10... what is its final form?
 
Okay, "part b" has $f= x^{10}+ y^{11}+ z$, $x= \sqrt{t+ s^2}$, $y=\frac{t}{s}$, $z= st$ and you want to find $\frac{\partial f}{\partial s}$ and $\frac{\partial f}{\partial t}$.

What are
$\frac{\partial f}{\partial x}$
$\frac{\partial f}{\partial y} $
$\frac{\partial f}{\partial z}$ ?

What are
$\frac{\partial x}{\partial s}$
$\frac{\partial x}{\partial t}$

$\frac{\partial y}{\partial s}$
$\frac{\partial y}{\partial t}$

$\frac{\partial z}{\partial s}$
$\frac{\partial z}{\partial t}$ ?

If you know basic Calculus you should be able to answer those.
If you can't do some of them, tell us which.

The "chain rule" says
$\frac{\partial f}{\partial s}= \frac{\partial f}{\partial x}\frac{\partial x}{\partial s}+ \frac{\partial f}{\partial y}\frac{\partial y}{\partial s}+ \frac{\partial f}{\partial z}\frac{\partial z}{\partial s}$
and
$\frac{\partial f}{\partial t}= \frac{\partial f}{\partial x}\frac{\partial x}{\partial t}+ \frac{\partial f}{\partial y}\frac{\partial y}{\partial t}+ \frac{\partial f}{\partial z}\frac{\partial z}{\partial t}$
 
I got my answers marked and lost a lot of marks actually. I'm not sure why.
 

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