Change for position to energy basis

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SUMMARY

The discussion focuses on computing the matrix elements Xmn of the position operator X in the energy basis, specifically using the eigenvectors of the Hamiltonian operator for a harmonic oscillator. The energy eigenvalues are defined as En=(1/2+n)hω. The matrix elements are expressed as Xmn=, and the completeness relation is suggested for converting the matrix into the energy basis representation. The algebraic formulation of the harmonic oscillator, involving the raising and lowering operators (a and a†), is crucial for this computation.

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  • Understanding of quantum mechanics and operators
  • Familiarity with the harmonic oscillator model
  • Knowledge of eigenvalues and eigenvectors in quantum systems
  • Proficiency in using ladder operators (a and a†)
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  • Learn about the algebraic formulation of the harmonic oscillator
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Homework Statement



Give expressions for computing the matrix elements Xmn of the matrix X representing the position operator X in the energy basis (using eigenvectors of the Harmiltonian operator)

Also told to consider the example of the harmonic oscillator where energy eigenvalues are En=(1/2+n)hω

Homework Equations



Xmn=<em|X|en>

H|en>=En|en>

The Attempt at a Solution



I'm thrown off a bit by how Xmn is defined here - if it is originally in the |x> basis, why is Xmn defined using |em> and |en>. Shouldn't these be inserted using the completeness relation to convert the matrix into the energy basis representation?

Here goes...
Xmn=<em|X|en>
Xmn=ƩƩ<em|x><x|X|x'><x'|en>
Xmn=ƩƩem(x)X(x,x')en(x')
 
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You can use the algebraic formulation of the harmonic oscilator and write X in terms of a and a^dagger. The action of a and a^dagger on the standard basis (eigenvectors of N and H) is already known, so...
 
dextercioby said:
You can use the algebraic formulation of the harmonic oscilator and write X in terms of a and a^dagger.

Sorry, still very confused!

So use -h2/2m d2ψ/dx2+1/2mω2x2ψ=Eψ how?
 
or use 1/2P2+1/2m2X2=H ?
 
No, X and P need to be replaced by the raising and the lowering ladder operators, a and a^{\dagger}. You should be familiar with them, I hope...
 
yes, got it now, thank you for the push in the right direction!
 

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