Change in a siren's volume question

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SUMMARY

The discussion centers on the phenomenon of an ambulance siren appearing louder as it approaches and quieter as it moves away. The primary explanation involves the concept of sound intensity and the geometry of sound wave propagation. When the siren approaches, sound waves are compressed, resulting in a higher intensity perceived by the listener. Conversely, as the siren moves away, the sound waves spread out, leading to a decrease in intensity. This effect is distinct from the Doppler effect, which primarily affects frequency rather than intensity.

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  • Understanding of sound wave propagation
  • Basic knowledge of sound intensity and distance
  • Familiarity with the Doppler effect
  • Concept of spherical wavefronts
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  • Research sound intensity and its relationship with distance from the source
  • Explore the Doppler effect in detail, focusing on frequency changes
  • Study the geometry of sound wave propagation in three dimensions
  • Investigate real-world applications of sound intensity principles
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Homework Statement


Q. Expalin why an ambulance siren gets louder as the ambulance approaches you and quieter as it drives away from you.


Homework Equations


None

The Attempt at a Solution


Hi,
So, I know it's not the Doppler effect, because this only affects frequency.
If the siren is only pointing in one direction, then the answer would be because the sound waves are directed at you when it's approaching and pointing away when it's moving away, yes?

However, if the siren is producing sound in all directions, I'm stuck. Is it something to do with the wavelengths being closer together on the approach, so there is more sound? But is this not the Doppler effect ie frequency?
 
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Doc Al said:
How does sound intensity depend on the distance from the source? Read this: http://hyperphysics.phy-astr.gsu.edu/Hbase/acoustic/invsqs.html#c1"

OK, but I don't see why that means it should be louder when it's approaching if the sound wave is being emitted in the shape of a sphere. Why isn't it just as loud when it's moving away?
 
Last edited by a moderator:
Pyroadept said:
OK, but I don't see why that means it should be louder when it's approaching if the sound wave is being emitted in the shape of a sphere. Why isn't it just as loud when it's moving away?
You are asked to explain why it gets louder as it approaches. There's a very simple reason for that!

Don't confuse this with "why is the sound louder when approaching". That's not the same thing. (And you're right, there's no reason why it would be any louder coming or going.)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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