Change in potential and kinetic energy

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SUMMARY

The change in potential energy (PE) is directly related to the change in kinetic energy (KE) in a system without non-conservative forces. For a tossed object, as it ascends, KE decreases while PE increases until it reaches its peak. At this point, PE is maximized, and as the object descends, PE decreases while KE increases. The relationship can be expressed mathematically, where the rate of change of potential energy equals the rate of change of kinetic energy, specifically represented as dp/dt = mgv and dE/dt = 1/2*m*2v*dv/dt, confirming their equality.

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Homework Statement


how is the change in potential energy related to the change in kinetic energy?


Homework Equations


i just know that for a tossed object, the KE decreases, and its PE increases until it reaches the top. Then it has potential energy at the top, and its KE increases, while its PE decreases. I am not sure how to relate the change in PE and KE though.


The Attempt at a Solution

 
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science_rules said:

Homework Statement


how is the change in potential energy related to the change in kinetic energy?


Homework Equations


i just know that for a tossed object, the KE decreases, and its PE increases until it reaches the top. Then it has potential energy at the top, and its KE increases, while its PE decreases. I am not sure how to relate the change in PE and KE though.


The Attempt at a Solution

It very much depends whether there are any non-conservative forces acting on the system. If there are no dissipative forces acting on the system then the sum of the kinetic and potential energies is constant.
 
Tha rate of change of potential eenrgy = dp/dt = mg*dh/dt = mgv
Rate of change of kinetic energy = dE/dt = 1/2*m*2v*dv/dt = mgv.
So they are equal.
 

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