Why Is My Temperature Change Calculation Incorrect?

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SUMMARY

The discussion centers on a user's incorrect calculation of temperature change using the equation \(\frac{440.022}{( \frac{23.43}{2.556 \times 10^{-8}})}\). The user initially arrived at an answer of \(4.80023 \times 10^{-6}\), which was identified as ten times larger than the correct value. Participants emphasized the importance of verifying units and assumptions regarding expected results. Additionally, they discussed the use of LaTeX for formatting mathematical expressions and alternatives like Microsoft Word for equation insertion.

PREREQUISITES
  • Understanding of basic algebra and temperature change calculations
  • Familiarity with LaTeX for mathematical formatting
  • Knowledge of unit conversion and dimensional analysis
  • Experience with Microsoft Word's equation editor
NEXT STEPS
  • Research LaTeX syntax and its applications in mathematical documentation
  • Explore dimensional analysis techniques to verify calculations
  • Learn about temperature change equations in physics
  • Investigate alternative math software for equation formatting and calculations
USEFUL FOR

Students in physics or mathematics, educators seeking to improve their teaching tools, and anyone involved in scientific calculations requiring precise mathematical formatting.

FFX
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Hey Everyone,

First time posting here, but you'll probably see me around quite a bit!
If this is in the wrong math spot please let me know, I don't understand the different types of maths.

I have an equation on the change of temperature, I substituted all the values in correctly and thought I was working it out correctly, but my answer came out far too low for me to think I did it correctly. If someone could have a look and give me guidance, that'd be great. The first picture is the full question, the second is me 'trying' to work it out! :(


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I think you went wrong on the very last step.
\frac{440.022}{( \frac{23.43}{2.556 \times 10^{-8}})}
Does not equal 4.80023 \times 10^-6. You've gotten it 10 times larger than it should be. But this is still a problem, because you said you were expecting a larger answer. Are you sure you've got all the units right?

P.S. Welcome to physics forum :)
 
Off topic, but What program did you use to show your work? I am taking online precalc and whatever program you are using would make my life much easier. Thanks!
 
who, me or ffx? I'm using latex, which physics forums 'supports' or however you call it.
 
This forum uses LaTeX, a math formatting language. You can use html tags [ tex ] and [ \tex ] (without the spaces) or, to fit it onto a line, [ itex ] and [ /itex ] (again without the spaces).

There is an introduction to its use here:
https://www.physicsforums.com/showthread.php?t=8997
 
I was curious about FFX's method. I was looking for something a little more user friendly than Latex. Perhaps I am getting the wrong impression.
 
Last edited:
hmm, I'm not sure how ffx wrote all that working, because he's put it on here as an image. Maybe message him, hope he answers?
 
Cheers for the replies!
Sorry for my delayed response, working full time and studying full time leaves me limited free time!

Thank you for correcting my mistake Bruce. I just 'assumed' the answer should be bigger. But a couple people on this site have already stated that there's no reason why I should assume a bigger answer when the question doesn't have any indication of what the size of the number should be! So the answer you provided would be correct, thank you!

@Neverquit
I didn't actually use any specific math program. I just used microsoft word. If you go 'insert' - 'equations' in microsoft word, you'll be given a toolbar with all the different math symbols. It's very easy to use but it doesn't work anything out for you automatically, everything must be typed in manually so it's a slow process.

I'm taking my math course externally, so I find microsoft word works for me as I can easily email off my assignment when necessary.
 
Thanks FFX, good luck with your studies!
 

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