Change in Temperature Equation HELP

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Homework Help Overview

The discussion revolves around an equation related to the change in temperature, where the original poster expresses confusion about their calculations and the resulting low answer. The context involves understanding the application of mathematical principles in a physics problem.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to substitute values into the temperature change equation but questions the validity of their result. Some participants suggest checking for errors in value entry and clarify the need for careful handling of mathematical operations. Others discuss the implications of using different software for calculations.

Discussion Status

Participants are actively engaging in identifying potential errors in the original poster's calculations and discussing the use of software tools. There is a focus on clarifying the mathematical setup and ensuring correct interpretation of the equation, with no explicit consensus reached yet.

Contextual Notes

The original poster mentions that they are working on this math unit externally without direct teacher support, which may contribute to their difficulties in understanding the problem and using Excel for calculations.

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Hey Everyone,

First time posting here, but you'll probably see me around quite a bit!
If this is in the wrong math spot please let me know, I don't understand the different types of maths.

I have an equation on the change of temperature, I substituted all the values in correctly and thought I was working it out correctly, but my answer came out far too low for me to think I did it correctly. If someone could have a look and give me guidance, that'd be great. The first picture is the full question, the second is me 'trying' to work it out! :(


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You should post this in the Homework and Coursework Questions subforum (read the forum rules).
 
"Put this into MS Excel"
... evil! I take it this is a course on how to use Excel?

Anyway - need to know how you went about it and how you know it came out too low.
That formula is utterly shocking - we'd normally simplify it.

looks like you didn't enter values correctly - I can see from 2nd to last line to last line you've misplaced a zero for example. But it is hard to tell.

You should use separate cells for your input data, then use the cell names as variables in your formula.
 
dalcde said:
You should post this in the Homework and Coursework Questions subforum (read the forum rules).


Oh I didn't notice that sticky, I'll post it in the homework area.


Simon Bridge said:
"Put this into MS Excel"
... evil! I take it this is a course on how to use Excel?

Anyway - need to know how you went about it and how you know it came out too low.
That formula is utterly shocking - we'd normally simplify it.

looks like you didn't enter values correctly - I can see from 2nd to last line to last line you've misplaced a zero for example. But it is hard to tell.

You should use separate cells for your input data, then use the cell names as variables in your formula.


It's not a course on how to use excel, the first part (part A) is supposed to be done just manually. The second part is supposed to be done on excel I presume. I don't even know how to use excel. I'm doing this math unit externally so it makes it a lot harder as I don't have a teacher telling me how to do anything.

I can't see the misplaced 0, could you be more specific on where it is please? Sorry.

I was just working it out following the basic BODMAS thing, brackets first etc.

I don't have the final answer there because already you can see it's going to come out to a very small number. I presume the question would be absolutely retarded if the temperature was only like 0.0000001 of a change lol.
 
Q/rcN=\frac{Q}{rcN} or Q/rcN=\frac{Q}{r}cN?
 
OK: so where it says "use program xyz" just use the program you have.
You could use OpenOffice-calc instead or any spreadsheet ... or matlab, or octave.

It's all multiplication and division so BODMAS may not get you into to much trouble ... bear in mind that a common error is to put 5-3+2=0 since it says to do the addition first. We can get rid of BEDMAS by being more careful how we write relations so 5-3+2 = (+5)+(-3)+(+2) and instead of divided-by signs we write fractions and so on.

Conventionally a/bc would be the same as a/(bc) ... the equation writer has been careful with 1/(2(Qs/Q)) and (r/c)f after all. (OTOH: has not been careful with variables - there is a r in the equation and an R in the text... guessing r=R?)

The missing zero, I think, is in the second term in the last line.
Code:
octave:174> 440.022/(23.43/0.00000002556)
ans =  4.8002e-07
... you have 4.8002e-06

I think you can expect a very small change in temperature from those figures and that equation - you have to do your reality-check against the physics: what is the situation that leads you to expect a larger temperature change?

If I put k=8.3e-06, and write Qs as Qs (for clarity) then that equation can be rewritten:\Delta T = \frac{kr^2Nf}{Q(1-\frac{Q}{2Q_s})}=\frac{2Q_skr^2Nf}{Q(2Q_s-Q)}... (check my algebra) you may find that easier to handle.
Note: the dimensions don't pan out - so either some units are missing ([k]=m-2 perhaps?) or the equation is wrong.
 
Thank you Simon!
I really appreciate the help! :)
 

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