Change potential energy without doing work?

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SUMMARY

The discussion centers on the concept of work in physics, specifically addressing the confusion surrounding potential energy changes when lifting an object at constant velocity. It is established that when a book is lifted at constant velocity, no net work is done by the person lifting it, as the force exerted equals the gravitational force acting on the book. However, the potential energy of the book increases as its height increases, which is consistent with the work-energy principle. The key takeaway is that while the potential energy increases, the work done by the person is balanced by the work done against gravity, resulting in no net work being performed.

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  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy theorem
  • Basic knowledge of potential and kinetic energy
  • Concept of constant velocity and forces acting on objects
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  • Study the work-energy theorem in detail
  • Explore the relationship between potential energy and gravitational force
  • Learn about energy conservation in closed and open systems
  • Investigate the implications of lifting objects at constant velocity
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Change potential energy without doing work?

I'm sure this is a very elementary question, however, this is just one thing that has been confusing me in my General Physics w/ Calculus 1 class...


They say, that if you are lifting a book at a constant velocity, no work is being done. This is because the acceleration going up, and gravity constant would have to be equal for the book to be moving at a constant velocity. This by itself i understand.

however.

later on in the course, we learned that Work=(delta kenetic energy)(force)..

and -(delta potential energy)=(delta kenetic energy)

also, by increasing the height of an object, you increase its potential energy.

SO.

as the book is rising, its gaining height...at this time its gaining potential energy... if its gaining potential energy, that also means that its kinetic energy is decreasing, which would change the numbers in the work formula...

how can one change potential energy without doing any work?

again: a person raising a book vertically at a constant velocity is doing no work, yet changing the books potential energy. Potential energy is inversely related to kinetic enerby. Kinetic energy is a major variable in the work formula, thus it would have to change the value of work. If the value of work is changing here, how come the person is doing no work?


maybe i haven't made a whole lot of sense typing it out, but it's confusing the hell out of me... if anyone can decipher what I've written here and come up with an explanation/clarification, i would very much appreciate it.
 
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You are doing work if you lift, say, a book from a low to a higher position (You pick it off the floor and put it on the table). You are exerting a force in the direction of motion (upwards), so the work done by you is positive and this work is equal to the change in potential energy of the object.
Before and after the deed the book is at rest. The book has gained potential energy, so the total energy has increased. That's okay, since this is not a closed system. You applied the external force by lifting the book. But if the book falls off the table, only gravity is acting on it, and it will do positive work on the book, increase its kinetic energy and decrease its potential energy according to energy conservation.
 
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