The electric field intensity at a point between two large parallel plates is 4.8 x 10^2 N/C.
What does the electric field become as a result of each of the following changes, considered separately:
a) when the amount of charge on each plate is tripled
b) when the plates are connected together by a conducting wire
for a, i think the electric field intensity would be tripled as well? i don't know which equation to look at to find the answer -- ε = kQ/r^2 doesn't seem right because there are two charges, one on each plate, and ε = V/d doesn't work because d doesn't come into play. i don't even have a guess for b). any explanation anyone could provide would be appreciated.