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Homework Help: Changes to electric field between two parallel plates

  1. Jul 27, 2008 #1
    1. The problem statement, all variables and given/known data

    The electric field intensity at a point between two large parallel plates is 4.8 x 10^2 N/C.
    What does the electric field become as a result of each of the following changes, considered separately:

    a) when the amount of charge on each plate is tripled
    b) when the plates are connected together by a conducting wire

    for a, i think the electric field intensity would be tripled as well? i don't know which equation to look at to find the answer -- ε = kQ/r^2 doesn't seem right because there are two charges, one on each plate, and ε = V/d doesn't work because d doesn't come into play. i don't even have a guess for b). any explanation anyone could provide would be appreciated.
  2. jcsd
  3. Jul 27, 2008 #2


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    Homework Helper

    a)How can you obtain the electric field given a highly symmetrical charge configuration?
    b)What do you expect to happen when there is potential difference across a conducting wire?
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