Changing bounds of integration of a double integral

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The discussion revolves around changing the bounds of integration for a double integral involving the area defined by the parabola y = x^2 and the line x = 1. Initially, the user attempted to set the bounds from x^2 to 1 for y and 0 to 1 for x, which did not yield the correct answer. After clarifying the region of integration, it was determined that the correct bounds should be from 0 to x^2 for y and 0 to 1 for x. The conversation highlights the importance of accurately visualizing the integration region to avoid errors. Ultimately, the correct interpretation of the bounds led to the right solution.
yopy
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Picture of the problem is listed above. I'm not sure how to switch the bounds of integration on it. Anyone here know how to go about this?

i tried doing it x^2 to 1 for y and then 0 to 1 for x but it didnt work out to be the write answer, the write answer after putting it in your calculator is about .40 ish

Normally when i do these kinds of problems i draw the bounds out, but I am not sure how these current bounds would even look.
 
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Hi yopy! :smile:

(try using the X2 tag just above the Reply box :wink:)
yopy said:
i tried doing it x^2 to 1 for y and then 0 to 1 for x but it didnt work out to be the write answer …

Well, that looks right to me …

it's just the area above the parabola y = x2

show us what you got.
 
i figured it out, the bounds turn into 0 to x^2 for respect to Y, and then 0 to 1 for respect to X

my problem was drawing the region they were integrating over. I got the right answer though, thanks.
 
tiny-tim said:
Hi yopy! :smile:

(try using the X2 tag just above the Reply box :wink:)


Well, that looks right to me …

it's just the area above the parabola y = x2


I don't think so. The limits of integration in the original problem indicate that the region is to the right of the parabola, not above it. The region is bounded by the parabola, the x-axis, and the line x = 1. Yopy's revised limits of integration describe this region.
 
oops!

Mark44 said:
I don't think so. The limits of integration in the original problem indicate that the region is to the right of the parabola, not above it. The region is bounded by the parabola, the x-axis, and the line x = 1. Yopy's revised limits of integration describe this region.

oops! :redface: i should have drawn it! :rolleyes:

thanks Mark! :smile:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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