Changing periods. Very confusing

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The discussion centers on proving that the function g(t) derived from a periodic function f(x) with a period of 2L has a period of 2π. By substituting t = πx/L, it is shown that g(t) = f(Lt/π) retains the periodicity. The key proof involves demonstrating that g(t) equals g(t + 2π) using the properties of f. The confusion arises from understanding the transformation and its implications on periodicity. Ultimately, the proof hinges on the relationship between the periods of f and g.
samh
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This is driving me nuts:

Suppose f(x) has period 2L, that is, f(x+2L)=f(x) for all x. If we let t=pi*x/L, and
g(t) = f(x) = f(L*t/pi)
then, as you can verify, g has period 2pi.

How do you show that that's true?!? How do you prove it? For the life of me I can't see how this holds despite the fact that I've wasted the past two hours working at it. I can't think of a technical explanation for it (a proof) OR an intuitive one... Please help.
 
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It's simple

f\left(\frac{Lt}{\pi}+2L\right)=f\left(\frac{L}{\pi}(t+2\pi)\right)=f\left(\frac{L}{\pi}t\right)

So you can see very clearly that if you denote by

g(t)=f\left(\frac{L}{\pi}t\right)

, then g has a period of 2\pi.

Daniel.
 
samh said:
This is driving me nuts:



How do you show that that's true?!? How do you prove it? For the life of me I can't see how this holds despite the fact that I've wasted the past two hours working at it. I can't think of a technical explanation for it (a proof) OR an intuitive one... Please help.


To prove it just show that g(t) = g(t+2pi) using the definition of g and the properties of f.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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