Changing the water levels of a lake

Kingyou123
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Homework Statement


Attached problem

Homework Equations


Anti-derivatives, linear approx. F(a)=f(a)+F'(a)(x-a)

The Attempt at a Solution


I'm stuck on the first part, I think (w')^-1(1)= W which is 1. It seems too easy... and for part c I'm having trouble finding the equation for the line. I figured that if I graph it on my calculator and use a regression test to find the equation
 

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Last edited:
on Phys.org
The attachment is way too zoomed out for me to read. Can you type the problem statement into the forum? That would help... :smile:
 
berkeman said:
The attachment is way too zoomed out for me to read. Can you type the problem statement into the forum? That would help... :smile:
updated it, sorry for that.
 
Is your question just the part that is checked: "(b) Explain what item iv means in terms of the city, lake, and IES budget"?

Item iv is "[itex](w^{-1})'(1)[/itex]". Since w(t) is the depth of water in the lake at time t, [itex]w^{-1}(x)[/itex] is the time at which the level of the lake is x. Then [itex](w^{-1})'(x)[/itex] is the rate at which time for the water to decrease amount x is changing.
 
HallsofIvy said:
Is your question just the part that is checked: "(b) Explain what item iv means in terms of the city, lake, and IES budget"?

Item iv is "[itex](w^{-1})'(1)[/itex]". Since w(t) is the depth of water in the lake at time t, [itex]w^{-1}(x)[/itex] is the time at which the level of the lake is x. Then [itex](w^{-1})'(x)[/itex] is the rate at which time for the water to decrease amount x is changing.
My question is on part a, I'm confused what(w')^-1(1) is. Thank you for help with part B :)
 
Last edited:

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