Charge Distribution on Spherical Conductors

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SUMMARY

The discussion centers on the charge distribution on spherical conductors, specifically a spherical conductor with a charge density of -5 units per unit volume and a surrounding thick spherical shell with a charge density of +2 units per unit volume. It is established that in electrostatic equilibrium, charges reside on the surface of conductors, with the interior charge density being zero. Additionally, the charge density on the surface is not uniform; it varies inversely with the radius of curvature, concentrating more in areas of higher curvature.

PREREQUISITES
  • Understanding of electrostatics and charge distribution principles
  • Familiarity with spherical conductors and their properties
  • Knowledge of Gauss's Law and its applications
  • Basic concepts of electric fields and potential
NEXT STEPS
  • Study Gauss's Law and its implications for charge distribution on conductors
  • Explore the concept of electric field strength in relation to surface charge density
  • Investigate the effects of charge density variations on electric fields
  • Learn about the behavior of charges in non-uniform electric fields
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics or charge distribution in conductors will benefit from this discussion.

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Homework Statement



given a spherical conductor with charge -5 units per unit volume, inside of a thick, spherical shell with charge +2 units per unit volume, where is the charge on the shell?

Homework Equations


conceptual questions


The Attempt at a Solution



this isn't a homework question,i just don't remember where charges go on a conductor.
are they always on the surface(s)?
are they distributed evenly throughout?

thanks!
 
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hi jehan60188! :smile:
jehan60188 said:
… where charges go on a conductor.
are they always on the surface(s)?
are they distributed evenly throughout?

from the pf library
In equilibrium, the charge inside a conductor is zero, and the density of charge at the surface is greater where the radius of curvature is less (and in the direction of increasing surface component of any applied field).​
 

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