Charge moving in cyclotron orbit

Click For Summary
SUMMARY

The angular frequency (omega) of a charged particle moving in a cyclotron orbit is derived from the relationship between the charge (q), mass (m), and magnetic field strength (B_0). The force acting on the particle due to the magnetic field is given by F = q(v × B), while the centripetal force required for circular motion is F = (m*v^2)/r. By equating these forces and using the relationship omega = v/r, one can express omega definitively in terms of q, m, and B_0. The discussion also seeks the Lagrangian of the system in plane polar coordinates.

PREREQUISITES
  • Understanding of magnetic fields and forces on charged particles
  • Familiarity with circular motion and centripetal force concepts
  • Knowledge of Lagrangian mechanics and polar coordinates
  • Basic algebra and vector cross product operations
NEXT STEPS
  • Derive the expression for omega in terms of q, m, and B_0
  • Study the application of Lagrangian mechanics in polar coordinates
  • Explore the implications of magnetic fields on charged particle motion
  • Investigate the relationship between angular frequency and particle velocity
USEFUL FOR

Physics students, educators, and researchers interested in electromagnetism, circular motion dynamics, and Lagrangian mechanics.

tarellan
Messages
5
Reaction score
0

Homework Statement



The particle moves in a plane perpendicular to the magnetic field direction as shown in the figure. What is omega, the angular frequency of the circular motion?

Express omega in terms of q, m, and B_0.


Homework Equations


32439.jpg


omega=2pi/T

The Attempt at a Solution



I found that At a given moment the particle is moving in the +x direction (and the magnetic field is always in the +z direction). If q is positive, the direction of the force on the particle due to the magnetic field is -y direction
 
Physics news on Phys.org
The force on a charged particle in a Magnetic Field B is given by F = q(v X B).

The force required to accelerate a particle of velocity v in a circular motion is related to the radius of the circular path and the mass of the particle by F=(m*v^2)/r

Omega can also be expressed as v/r.

By equating the two forces and playing around a bit I'm sure you'll come out with your answer.
 
can anyone give the Lagrange of the system in plane polar coordinates?
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
892
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
Replies
1
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
2K