- #1

Fluxthroughme

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**1. What must the charge of a 1.45g particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 650N/C?**

## Homework Equations

[tex]E = \frac{F}{q}[/tex]

## The Attempt at a Solution

So the field is pointing downwards. E fields point in the direction a positive charge would take, so the charge must be negative to stay balanced. Gravity is also pointing downwards.

So I take the above formula, and I get F = Eq = ma

[tex]q = \frac{(1.45*10^{-3})*g}{650} = 1.488*10^{-16} C[/tex]

(Using g = [itex]6.67*10^{-11}[/itex]) However the answer given is [itex]-21.9\mu C[/itex]

Not sure what I'm doing wrong/missing here?