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Charge on the Capacitor at a Specific Time

  1. Dec 10, 2012 #1
    1. The problem statement, all variables and given/known data

    The switch in the RC circuit shown in the figure is closed at t=0.

    What is the charge on the capacitor at the time t = .35 ms?

    I'm 95% sure I'm using the right formula but it's not working so I was wondering if I was possibly confusing something?

    2. Relevant equations

    q(t)= CV(1-e^(-t/RC))

    3. The attempt at a solution

    q(t)= CV(1-e^(-t/RC))
    = (62*10^-6)(15 V)(1 - e^(-.00035/(10.8*(62*10^-6)))
    = 3.78*10^-4 C ----> this is definitely wrong because the answer is asked for in mC -> any ideas?
     
  2. jcsd
  3. Dec 10, 2012 #2

    Curious3141

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    Homework Helper

    Figure's missing.

    You got an answer in C, but you can certainly express it in mC (millicoulomb), can't you? Are you saying that that answer is not accepted?
     
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