Charge on the Capacitor at a Specific Time

[brittydagal]

Homework Statement

The switch in the RC circuit shown in the figure is closed at t=0.

What is the charge on the capacitor at the time t = .35 ms?

I'm 95% sure I'm using the right formula but it's not working so I was wondering if I was possibly confusing something?

Homework Equations

q(t)= CV(1-e^(-t/RC))

The Attempt at a Solution

q(t)= CV(1-e^(-t/RC))
= (62*10^-6)(15 V)(1 - e^(-.00035/(10.8*(62*10^-6)))
= 3.78*10^-4 C ----> this is definitely wrong because the answer is asked for in mC -> any ideas?

 

[Curious3141]

Figure's missing.

You got an answer in C, but you can certainly express it in mC (millicoulomb), can't you? Are you saying that that answer is not accepted?