- #1

Kosta1234

- 46

- 1

- Homework Statement
- Charged Capacitor

- Relevant Equations
- -

Why when a capacitor is fully charged the circuit is acting like an open circuit?

And what is the meaning of "fully charged", if the charge as a function of time equation is:

$$ Q = CV_b [1 - e^{\frac{t}{RC}}] $$

so by this equation the charge on the capacitor will never reach exactly, Q = CV, only when the time goes to infinity.Edit:

Mayble I should be more precise, why in the following question the current to the right side of the circuit is stopping immediately after the capacitor is charged (In the answer it have been said that the capacitor is fully charged immediately after closing the switch),

If there was a resistor in the right side of the circuit, could I've also say that the capacitor is fully charged immediately?

immediately

thank you.

And what is the meaning of "fully charged", if the charge as a function of time equation is:

$$ Q = CV_b [1 - e^{\frac{t}{RC}}] $$

so by this equation the charge on the capacitor will never reach exactly, Q = CV, only when the time goes to infinity.Edit:

Mayble I should be more precise, why in the following question the current to the right side of the circuit is stopping immediately after the capacitor is charged (In the answer it have been said that the capacitor is fully charged immediately after closing the switch),

If there was a resistor in the right side of the circuit, could I've also say that the capacitor is fully charged immediately?

immediately

thank you.