Charge Redistribution in Unequal Capacitors with an Inductor

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When two unequal capacitors with equal charges are connected in series with an inductor, charge redistribution occurs until the voltage across each capacitor is equal. The equations governing this process are Q'_1 C_1 = Q'_2 C_2 and Q'_1 + Q'_2 = Q_1 - Q_2. The charges will adjust until the potential difference across both capacitors stabilizes. This redistribution is driven by the need for equal voltage, leading to a new equilibrium state. Ultimately, the system reaches a point where the voltage across each capacitor is uniform, ensuring charge conservation.
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we have 2 capacitors having unequal capacities and eual charges both are connected to each other in a way such that the positive terminal of one capacitance is connected to the negative terminal of the othere capacitance and vice versa,and between these capacitances we have an induator,how will the charges redistribute themselves,and why?
 
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please answer
 
After connection, V on each C must be the same.
There are two equations:
Q'_1 C_1=Q'_2 C_2,
Q'_1+Q'_2=Q_1-Q_2.
Solve them.
 
the charges will move until the pd across them is the same.
 
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