The Attempt at a Solution
I will name the top left capacitor A , bottom left capacitor B and right capacitor C .
Before the switch is closed , charges on A and B will be 20 μC each and that on C will be 40 μC .
After the switch is closed ,both A and B will be shorted . Charge on C will be 60μC .
A and B will get discharged i.e there will be no charge on A and B .
On doing further calculations I am getting all four options correct .
The correct answer i.e incorrect statement is 3) .
But if charge on C changes from 40μC to 60μC , doesn't this mean 20 μC has flown through the battery and battery has done 0.6 mJ work or 0.6 mJ energy is supplied by the battery ?
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