Charge Volume Density To Charge Per Unit Length

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SUMMARY

The discussion focuses on converting charge volume density to linear charge density in the context of a cylindrical insulator surrounding a wire. The method involves calculating the volume of the insulator using the formula for the volume of a cylinder, specifically π(r2² - r1²) multiplied by the unit length. The total charge is then found by multiplying the volume by the charge volume density (ρ), and the linear charge density is obtained by dividing the total charge (Q) by the length (l). The example provided uses specific values, demonstrating the calculation process clearly.

PREREQUISITES
  • Understanding of charge volume density and linear charge density
  • Familiarity with the geometry of cylinders, specifically volume calculations
  • Knowledge of basic physics equations related to charge and electric fields
  • Ability to manipulate mathematical expressions involving π and squared terms
NEXT STEPS
  • Study the derivation of the volume of a cylinder and its application in electrostatics
  • Learn about charge density concepts in electrostatics and their implications
  • Explore the relationship between linear charge density and electric field strength
  • Investigate practical applications of charge density calculations in electrical engineering
USEFUL FOR

Students studying electromagnetism, physics educators, and electrical engineering professionals seeking to deepen their understanding of charge density calculations and their applications in real-world scenarios.

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Homework Statement


http://imgur.com/VzZjSEH

I took a screen shot so I did not leave anything out.


Homework Equations


Surface area, and volume of a sphere.


The Attempt at a Solution



I am trying to find the linear charge density from the charge volume density. I got it explained from a friend. It was right, but made no sense. He did it by taking the volume density, and multiplying it by the charge volume density by pi, and (outer r2 - inner r2).

So he did -657 * pi * (.0422 - .0262)

Can someone explain to me how this is right?
 
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It's the total charge per unit length due to the outer insulator. Charge = voume charge density x volume. The volume of the insulator is pi(r2^2 - r1^2) x 1 unit length. Multiply by the charge density rho and you have your answer.

Of course, the complete answer must include the linear charge density of the wire as well.
 
Calculate the total charge Q of a length ##l## of the insulator. Then divide Q by ##l##.
 

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