Charged ring with oscillating particle

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SUMMARY

A charged ring with a radius of 6 cm carries a uniform positive charge of 7 μC, while a particle with a mass and a charge of -7 μC oscillates about the center of the ring with an angular frequency of 15 rad/s. When the radius of the ring is doubled, the linear charge density remains constant, affecting the angular frequency of the oscillation. The relationship between the force exerted by the electric field and the oscillation can be analyzed using the equation F = kQq/r², leading to a new angular frequency that can be derived from the principles of simple harmonic motion (SHM).

PREREQUISITES
  • Understanding of electrostatics, particularly Coulomb's law
  • Familiarity with simple harmonic motion (SHM) concepts
  • Knowledge of electric fields generated by charged objects
  • Ability to manipulate equations involving angular frequency and linear charge density
NEXT STEPS
  • Research the electric field along the axis of a charged ring
  • Study the derivation of angular frequency in simple harmonic motion
  • Explore the effects of varying charge distributions on oscillation frequencies
  • Investigate the relationship between radius and charge density in oscillatory systems
USEFUL FOR

Students in physics, particularly those studying electromagnetism and oscillatory motion, as well as educators looking for practical examples of charged particle dynamics in electric fields.

nautola
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Homework Statement


A ring of radius 6 cm that lies in the yz
plane carries positive charge of 7 μC uniformly
distributed over its length. A particle of mass
m carrying a charge of −7 μC executes small
oscillations about the center of the ring on its
axis with an angular frequency of 15 rad/s.
Find the angular frequency of oscillation of
the mass if the radius of the ring is doubled
while keeping the linear charge density on the
ring constant.


Homework Equations


F = kQq/r2




The Attempt at a Solution



I don't even know where to start with this one. To be honest, I'm not entirely sure what's actually going on. Is the particle going around the ring? Is it going right through it? I have no idea.
 
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Due to the simitry, the field at the centre of the ring is zero. Search for an expression for a field along the axis of a charged ring in the web. Since distance x is very small, neglect the higher power of x in the expression. Now F = E( - q) = ma. And since in SHM, a = -ω2x, you can compare the two angular velocities.
 

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