- #1
SlyCedix
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Homework Statement
The electric field on the axis of a uniformly charged ring has magnitude 360 kN/C at a point 6.2 cm from the ring center. The magnitude 19 cm from the center is 150 kN/C ; in both cases the field points away from the ring.
Homework Equations
1. Find the ring's radius.
2. Find the ring's charge.
The Attempt at a Solution
E=kxQ/(x2 + a2)3/2
360000 = kQ(.062)/(.0622+a2)3/2
150000 = kQ(.19)/(.192+a2)3/2
360/150 = (.062/.19) * ((.0622+a2)/(.192+a2))3/2
(360/150 * .19/.062)2/3 = (.0622+a2)/(.192+a2)
(360/150 * .19/.062)2/3 * (.192+a2)= .0622+a2
(360/150 * .19/.062)2/3 * (.192) - .0622 = a2 - (360/150 * .19/.062)2/3 * a2)
-0.00247871714 = -2.7819469745 a^2
a = sqrt(0.00247871714/2.7819469) = .030 m = 3.0 cm
Which turned out to be incorrect, and with an incorrect radius, I've got nothing to go off of for charge
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