Electric field of ring causing oscillation

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SUMMARY

The discussion focuses on calculating the angular frequency of a charged particle oscillating about the center of a uniformly charged ring. The ring has a radius of 18 cm and carries a positive charge of 5 µC, while the particle has a mass and a charge of -5 µC. The initial angular frequency of oscillation is given as 12 rad/s. When the radius of the ring is doubled to 36 cm, the new angular frequency can be determined using the relationship between the electric field and the force acting on the particle, applying the formula for angular frequency in a mass-spring system.

PREREQUISITES
  • Understanding of electric fields, specifically the electric field of a uniformly charged ring.
  • Knowledge of simple harmonic motion and the analogy to mass-spring systems.
  • Familiarity with the formula for angular frequency: ω = (k/m)^(1/2).
  • Basic calculus for manipulating equations involving electric fields and forces.
NEXT STEPS
  • Calculate the new angular frequency of oscillation for a ring radius of 36 cm using the electric field formula.
  • Explore the derivation of the electric field of a uniformly charged ring in detail.
  • Study the relationship between force, mass, and angular frequency in oscillatory systems.
  • Investigate the effects of varying charge distributions on oscillation frequencies.
USEFUL FOR

Students studying electromagnetism, physics enthusiasts, and anyone interested in the dynamics of charged particles in electric fields.

ponyhunter
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Homework Statement


A ring of radius 18 cm that lies in the yz plane
carries positive charge of 5 µC uniformly distributed over its length. A particle of mass m
that carries a charge of −5 µC executes small
oscillations about the center of the ring on its
axis with an angular frequency of 12 rad/s.
Find the angular frequency of oscillation of
the mass if the radius of the ring is doubled to
36 cm and all other parameters above remain
unchanged.


Homework Equations


{Hint: it is useful to draw an analogy between this problem and a mass-spring system.
For the latter, the force on the mass is given by
F = ma = −kx and produces 1d simple harmonic oscillation with an angular frequency
of ω = (k/m)^(1/2)}

Electric field of a uniformly charged ring: (1/(4*pi*epsilon))*q*z/(R^2+z^2)^(3/2)

The Attempt at a Solution

Well I took the electric field of the ring and multiplied it by the charge of the particle mass to get the force. I also took the angular frequency and squared it to get k/m, but after that I'm just stuck. I really just wish I knew what to do. Thanks for your help. I really appreciate it.
 
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ponyhunter said:

Homework Statement


A ring of radius 18 cm that lies in the yz plane
carries positive charge of 5 µC uniformly distributed over its length. A particle of mass m
that carries a charge of −5 µC executes small
oscillations about the center of the ring on its
axis with an angular frequency of 12 rad/s.
Find the angular frequency of oscillation of
the mass if the radius of the ring is doubled to
36 cm and all other parameters above remain
unchanged.


Homework Equations


{Hint: it is useful to draw an analogy between this problem and a mass-spring system.
For the latter, the force on the mass is given by
F = ma = −kx and produces 1d simple harmonic oscillation with an angular frequency
of ω = (k/m)^(1/2)}

Electric field of a uniformly charged ring: (1/(4*pi*epsilon))*q*z/(R^2+z^2)^(3/2)

The Attempt at a Solution

Well I took the electric field of the ring and multiplied it by the charge of the particle mass to get the force. I also took the angular frequency and squared it to get k/m, but after that I'm just stuck. I really just wish I knew what to do. Thanks for your help. I really appreciate it.

The question says that charge performs oscillations near the centre of the ring. This means that z (assuming it is the distance of charge from centre of ring) is much smaller than the radius of ring (R) i.e z<<R. Use this approximation and find the force on the charge.
 

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