Charges near a conducting plane

Click For Summary
SUMMARY

The discussion focuses on the configuration of charges and conducting planes, specifically analyzing the method of image charges. It establishes that only conducting planes oriented at 90° can be effectively solved using this method, while configurations involving a point charge on the bisector of a 120° dihedral angle present challenges due to the inability to maintain constant potential at the planes. Participants confirm that other angles may also be solvable, but the specifics remain unclear.

PREREQUISITES
  • Understanding of electrostatics and charge interactions
  • Familiarity with the method of image charges
  • Knowledge of equipotential surfaces
  • Basic principles of conducting materials in electrostatics
NEXT STEPS
  • Research the method of image charges in electrostatics
  • Study equipotential surfaces and their properties
  • Explore configurations of point charges near conducting planes
  • Investigate the behavior of charges in non-orthogonal arrangements
USEFUL FOR

Students and professionals in physics, particularly those studying electrostatics, as well as educators seeking to understand complex charge configurations and their implications in theoretical scenarios.

JSGandora
Messages
92
Reaction score
0

Homework Statement


Locate two charges q each and two charges –q each on the corners of a square, with like charges diagonally opposite on another. Show that there are two equipotential surfaces that are planes. In this way obtain, and sketch qualitatively, the field of a single point charge located symmetrically in the inside corner formed by being a metal sheet through a right angle. Which configurations of conducting planes and point charges can be solved this way and which can’t? How about a point charge located on the bisector of a 120° dihedral angle between two conducting planes?

Homework Equations

The Attempt at a Solution



I understand this is an extension of the method of image charges and I think that only conducting planes at 90° to each other can be solved in this way. For the 120° case, the image charges lie on the plane of the two conducting planes and there is no good way to introduce another image charge so that the potential at the planes is constant. Is this correct?
 
Physics news on Phys.org
JSGandora said:
For the 120° case, the image charges lie on the plane of the two conducting planes and there is no good way to introduce another image charge so that the potential at the planes is constant.
That looks right to me.
JSGandora said:
I think that only conducting planes at 90° to each other can be solved in this way.
No, I believe there are other angles. Which ones won't have the problem you mentioned in respect of 120 degrees?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
1K
Replies
21
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 9 ·
Replies
9
Views
10K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K