Understanding Trigonometric Transformations: Analyzing a Horizontal Translation

  • Thread starter aisha
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In summary, we changed the original function to y=2\cos [\frac {-1} {2} (x-180)] -3, with a period of -4pi, amplitude of 2, max value of -1, min value of -5, and a range of -5<=y<=-1. The domain is all real numbers, with a vertical displacement of 3 units down and a horizontal translation of 180 units to the right. The original question had 90 degrees in it, and the horizontal translation should be to the right, not left.
  • #1
aisha
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[tex] y=2\cos (\frac {-1} {2}x + 90 ) -3 [/tex]

I changed the original function to

[tex] y=2\cos [\frac {-1} {2} (x-180)] -3 [/tex]

period=-4pi
amplitude=2
max=-1
min=-5
range={y:-5<=y<=-1}
domain={x:XER}
vertical displacement 3 units down
horizontal translation 180 units left
 
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  • #2
We can't tell- there is no "x" in the original function.
 
  • #3
aisha: do not confuse radians and degrees.
 
  • #4
I don't think I am confused about radians and degrees some of my trig functions have radians in them so to make things simpler I convert to degrees but in this question i haven't done any converting that 90 is in degrees. :smile:
sorry I added the x in the original function.
 
  • #5
Did i do this question correctly?
 
  • #6
Yes, seems correct although I think the horizontal displacement is to the right.
 
  • #7
If the original question had 90 in it, then you did it correctly except for the direction of the horizontal translation. If the original question had [itex]\frac{\pi}{2}[/itex] in it, then the value of the horizontal translation is off too.
 
  • #8
thanks so much the original question does have 90 degrees in it. You are right the horizontal translation should be to the right NOT LEFT! :smile:
 

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