Calculating Amplitude in Standard Model

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SUMMARY

The forum discussion centers on the calculation of amplitude in the Standard Model, specifically regarding the contributions from three diagrams at the lowest order. The user presented an amplitude formula involving Higgs bosons and fermions, which was confirmed to be mostly correct. However, it was noted that the third term in the amplitude calculation requires an additional factor of λ in the numerator to accurately represent the Higgs boson exchange. This correction is crucial for the proper evaluation of the amplitude.

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Homework Statement
Draw the Feynman diagrams contributing to the process ##\mu^+ \mu^- \rightarrow H + H## at the lowest electroweak order and calculate the squared amplitude
Relevant Equations
Vertex of the Feynman diagrams between two fermions and the Higgs boson is ##i\frac{m}{v}##, and the triple interaction vertex of the Higgs boson is ##i \lambda v## where ##m## is the muon's mass, ##v## is the vacuum expectation value of the Higgs boson, and ##\lambda## is its coupling constant.
Hi! I'd like to ask you if my calculation of the amplitude on the mentioned process in the Standard Model is correct. The three diagrams contributing at lowest order should be
1637926237606.png

where in the middle one the two Higgs boson are NOT forming a quartic interaction vertex.
My attempt at calculating the (not yet squared) amplitude is this: $$A = \bar{v}(p_2) \left( \frac{im}{v} \frac{i}{\gamma^\mu(p_1-p_3)_\mu} \frac{im}{v} + \frac{im}{v} \frac{i}{\gamma^\mu(p_1-p_4)_\mu} \frac{im}{v} + \frac{im}{v} \frac{i}{q^2 - M_H^2 +i\Gamma_H M_H} i \lambda v \right) u(p_1)$$ Is this right?
 
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Thanks!Yes, that is correct. However, note that the third term should include a factor of $\lambda$ in the numerator (i.e., it should be $\frac{im\lambda}{v}\frac{i}{q^2 - M_H^2 +i\Gamma_H M_H}i\lambda v$). This is because this term corresponds to the exchange of a single Higgs boson between the two fermions, and thus the vertex should include a factor of $\lambda$.
 

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