Check invariance under time-reversal?

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FilipLand
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Hi!

How do I check if the equation of motion of the particle, with a given potential, is invariant under time reversal?

For a 2D pointlike particle with potential that is e.g $$V(x) = ae^(-x^2) + b (x^2 + y^2) +cy', where a,b,c >0$$

Can it be done by arguing rather then computing?

Thanks!
 
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Orodruin said:
Your potential seems constant ...

How come? And what would that mean in this context? That we can tell if the particle move back or forward in time since potential is constant?
 
Vanadium 50 said:
There is a y-prime in it.
yes it is
 
Orodruin said:
Then it is not a potential.

I get your point, that it's not a function of time. Thanks. But FYI it's wrong to say something is not a potential due to time independency.
 
Orodruin said:
I never said that. I said that it is not a potential because it contains a time derivative of the coordinates.

Why wouldn't it be? I have an example exercise where that is the potential we work with?
 
Orodruin said:
Because the potential is a function of the coordinates only. Not of time derivatives of the coordinates. Please give more details of what you are reading.

The statement was not true in this case, you can notice in which direction time flows! The time derivative term is a friction term which is not time reversible.
 
FilipLand said:
The statement was not true in this case, you can notice in which direction time flows! The time derivative term is a friction term which is not time reversible.
A friction term is not part of any potential because friction is not conservative. It is misleading to include friction terms as "potential" terms.