Checking that a coherent state is an eigenfunction of an operator

Click For Summary

Homework Help Overview

The discussion revolves around the properties of coherent states in quantum mechanics, particularly in relation to their status as eigenfunctions of an operator, likely within the context of a harmonic oscillator.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the nature of the physical system, questioning whether it is indeed a harmonic oscillator. They discuss the implications of the lowering operator and its effects on energy eigenstates. There are attempts to manipulate summations and indices to clarify the relationship between coherent states and eigenvalues.

Discussion Status

The discussion includes various interpretations of the problem, with participants providing insights and guidance on the mathematical manipulations involved. Some participants express confusion, while others confirm the correctness of the approaches taken, indicating a productive exchange of ideas.

Contextual Notes

There is a mention of the problem's lack of explicit identification of the physical system, which leads to some uncertainty in the assumptions being made. Additionally, participants express feelings of confusion and self-doubt regarding their understanding of the topic.

Dixanadu
Messages
250
Reaction score
2

Homework Statement


Hey guys, I'll type this thing up in Word.

http://imageshack.com/a/img716/8219/wycz.jpg
 
Last edited by a moderator:
Physics news on Phys.org
What is the physical system in question, is it a harmonic oscillator? If it is, then the lowering operator acts on the energy eigenstates as ##\hat{a}\psi_{n}(x)=\sqrt{n}\psi_{n-1}(x)##. This is the only info you need in order to solve the problem.
 
The question doesn't say that it is a harmonic oscillator, but it does say that "these states closely resemble classical particles" so I think you're right. If I do as you say, I end up with this:
http://imageshack.com/a/img69/8361/loix.jpg
 
Last edited by a moderator:
The lowering operator annihilates the ground state: ##\hat{a}\psi_{0}(x)=0##. Also, you can change the variable over which the summation is, e.g. ##k=n-1##. That way you should be able to show that acting on the coherent state with the lowering operator is equivalent to multiplying with a constant.
 
Okay I'm lost...T_T Is this what you mean?
http://imageshack.com/a/img703/889/xvhg.jpg

I feel kinda stupid now ¬_¬
 
Last edited by a moderator:
After you change the index, the summation should be from ##k=0## to ##k=\infty## and the exponent of ##\lambda## becomes ##k+1##...
 
So you mean this?
http://imageshack.com/a/img842/8932/5a4q.jpg

which means that the eigenvalue is just...λ?
 
Last edited by a moderator:
Yes, that's the correct answer.
 
Wow thank you :d !
 
  • #10
that was supposed to be all caps but i guess it got filtered :(
 

Similar threads

Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
3K