Checking that a given potential has a ground state

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Homework Help Overview

The discussion revolves around a potential given in quantum mechanics, specifically examining whether the potential \( V(x) = -\frac{h^2 a^2}{m}\text{sech}^2(ax) \) has a ground state represented by the wavefunction \( \psi_0(x) = A\text{sech}(ax) \). Participants are exploring the implications of the time-independent Schrödinger equation in confirming the existence of this ground state.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss substituting the potential into the Schrödinger equation to verify if \( \psi_0 \) is indeed a solution. There are questions about whether this approach sufficiently demonstrates that \( \psi_0 \) is the ground state, and concerns about the implications of the solutions obtained.

Discussion Status

Some participants have referenced external sources to support their understanding of ground states and nodes in wavefunctions. There is an ongoing exploration of the relationship between the number of nodes in a wavefunction and its energy level, with some guidance being offered regarding the properties of ground states in one-dimensional systems.

Contextual Notes

Participants are considering the implications of the number of nodes in the wavefunction and how it relates to energy levels, as well as the specific characteristics of the potential in question. There is an acknowledgment of the need for deeper understanding rather than just verifying solutions.

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Homework Statement
Checking that a given potential has a ground state
Relevant Equations
$$V(x) = -\frac{h^2 a^2}{m}\text{sech}^2(ax)$$
In my book the following potential is given:

$$V(x) = -\frac{h^2 a^2}{m}\text{sech}^2(ax)$$

then the task is: Check that this potential has the ground state ##\psi_0(x) = A\text{sech}(ax)##.

I first thought to put it in the time-independent Schrödinger equation and show that it is a solution, but surely that just shows that it satisfies the Schrödinger equation. The question is to show that the potential has a ground state equal to ##\psi_0##. I spent all day on this problem when I was right in the beginning: just jam it into the Schrödinger equation and out comes its ground state energy times itself. But by doing that are we actually showing that the GROUND STATE is given by ##\psi_0##? That is, are the solutions to this problem incorrect? Is there something missing?

Just to clarify what the solutions are saying: they show that ##\psi_0## satisfies

$$-\frac{h^2}{2m} \frac{d^2\psi_0}{dx^2} + V\psi_0 = E \psi_0$$
 
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hmparticle9 said:
I spent all day on this problem when I was right in the beginning: just jam it into the Schrödinger equation and out comes its ground state energy times itself. But by doing that are we actually showing that the GROUND STATE is given by ##\psi_0##? That is, are the solutions to this problem incorrect? Is there something missing?
The number of nodes of the wavefunction is related to the energy level.
 
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hmparticle9 said:
https://en.wikipedia.org/wiki/Ground_state

Says here that in one-dimension it can be proven that the ground state has no nodes. Thanks for putting me on the right track :)
That's what it says, but do you have an intuitive idea why that might be the case? What is the connection between energy and number of nodes?
hmparticle9 said:
I first thought to put it in the time-independent Schrödinger equation and show that it is a solution, but surely that just shows that it satisfies the Schrödinger equation.
Surely it does. Did you do it?
 
The connection between energy and number of nodes is that the energy increases as the number of nodes increases?

Yes I did it. :)
 

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