MHB Chemistry: Balancing Redox reactions

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The redox reaction provided is balanced correctly in acidic solution as 5Sn(s) + 2MnO4−(aq) + 16H+(aq) → 5Sn2+(aq) + 2Mn2+(aq) + 8H2O. However, there are concerns regarding the notation, specifically the placement of subscripts and superscripts. MnO4 should be written as MnO4− to accurately reflect its charge. Including phases in the final equation is essential for clarity. Ensuring proper chemical notation is crucial for homework acceptance.
needOfHelpCMath
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What do i have wrong here for my chemical equation? Seems to be right but my homework won't accept it.

Balance the redox reaction occurring in acidic solution.

Sn(s)+MnO−4(aq) → Sn2+(aq)+Mn2+(aq)

Express your answer as a chemical equation including phases.
5Sn+2MnO−4+16H+→5Sn2++2Mn2++8H2O


is this correct?
 
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needOfHelpCMath said:
What do i have wrong here for my chemical equation? Seems to be right but my homework won't accept it.

Balance the redox reaction occurring in acidic solution.

Sn(s)+MnO−4(aq) → Sn2+(aq)+Mn2+(aq)

Express your answer as a chemical equation including phases.
5Sn+2MnO−4+16H+→5Sn2++2Mn2++8H2O


is this correct?

Hi needOfHelpCMath!

It seems correct to me, although the question does ask to include phases.
So should it perhaps be:
$$Sn(s)+MnO^−_4(aq) → Sn^{2+}(aq)+Mn^{2+}(aq)$$
$$5Sn(s)+2MnO^−_4(aq) + 16H^+(aq)→ 5Sn^{2+}(aq)+2Mn^{2+}(aq) + 8H_2O
$$
(Wondering)
 
I like Serena said:
Hi needOfHelpCMath!

It seems correct to me, although the question does ask to include phases.
So should it perhaps be:
$$Sn(s)+MnO^−_4(aq) → Sn^{2+}(aq)+Mn^{2+}(aq)$$
$$5Sn(s)+2MnO^−_4(aq) + 16H^+(aq)→ 5Sn^{2+}(aq)+2Mn^{2+}(aq) + 8H_2O
$$
(Wondering)

So inputed your answer and it said "Check your placement of subscripts and super subscripts"
 
needOfHelpCMath said:
So inputed your answer and it said "Check your placement of subscripts and super subscripts"

Perhaps MnO-4 should be the other way around. That is, it should be MnO4-, since it's really $(MnO_4)^-$. (Thinking)
 
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