MHB Chemistry: Balancing Redox reactions

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The redox reaction provided is balanced correctly in acidic solution as 5Sn(s) + 2MnO4−(aq) + 16H+(aq) → 5Sn2+(aq) + 2Mn2+(aq) + 8H2O. However, there are concerns regarding the notation, specifically the placement of subscripts and superscripts. MnO4 should be written as MnO4− to accurately reflect its charge. Including phases in the final equation is essential for clarity. Ensuring proper chemical notation is crucial for homework acceptance.
needOfHelpCMath
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What do i have wrong here for my chemical equation? Seems to be right but my homework won't accept it.

Balance the redox reaction occurring in acidic solution.

Sn(s)+MnO−4(aq) → Sn2+(aq)+Mn2+(aq)

Express your answer as a chemical equation including phases.
5Sn+2MnO−4+16H+→5Sn2++2Mn2++8H2O


is this correct?
 
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needOfHelpCMath said:
What do i have wrong here for my chemical equation? Seems to be right but my homework won't accept it.

Balance the redox reaction occurring in acidic solution.

Sn(s)+MnO−4(aq) → Sn2+(aq)+Mn2+(aq)

Express your answer as a chemical equation including phases.
5Sn+2MnO−4+16H+→5Sn2++2Mn2++8H2O


is this correct?

Hi needOfHelpCMath!

It seems correct to me, although the question does ask to include phases.
So should it perhaps be:
$$Sn(s)+MnO^−_4(aq) → Sn^{2+}(aq)+Mn^{2+}(aq)$$
$$5Sn(s)+2MnO^−_4(aq) + 16H^+(aq)→ 5Sn^{2+}(aq)+2Mn^{2+}(aq) + 8H_2O
$$
(Wondering)
 
I like Serena said:
Hi needOfHelpCMath!

It seems correct to me, although the question does ask to include phases.
So should it perhaps be:
$$Sn(s)+MnO^−_4(aq) → Sn^{2+}(aq)+Mn^{2+}(aq)$$
$$5Sn(s)+2MnO^−_4(aq) + 16H^+(aq)→ 5Sn^{2+}(aq)+2Mn^{2+}(aq) + 8H_2O
$$
(Wondering)

So inputed your answer and it said "Check your placement of subscripts and super subscripts"
 
needOfHelpCMath said:
So inputed your answer and it said "Check your placement of subscripts and super subscripts"

Perhaps MnO-4 should be the other way around. That is, it should be MnO4-, since it's really $(MnO_4)^-$. (Thinking)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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