Chemistry Calculate the oxidation no.

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SUMMARY

The oxidation numbers of nitrogen in ammonium nitrate (NH4NO3) are +1 and +5. The calculation involves recognizing that the oxidation state of hydrogen is +1 and oxygen is -2. The ammonium ion (NH4) contributes +1 to the overall charge, while the nitrate ion (NO3) contributes -1, leading to nitrogen oxidation states of -3 in NH4 and +5 in NO3. This demonstrates that the two nitrogen atoms in NH4NO3 have different oxidation states.

PREREQUISITES
  • Understanding of oxidation states in chemistry
  • Familiarity with the ammonium ion (NH4)
  • Knowledge of the nitrate ion (NO3)
  • Basic algebra for balancing chemical equations
NEXT STEPS
  • Study the rules for determining oxidation states in various compounds
  • Learn about the properties and reactions of ammonium and nitrate ions
  • Explore examples of compounds with multiple oxidation states
  • Investigate the significance of oxidation states in redox reactions
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Radwa Kamal
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Homework Statement


Calculate the oxidation no. of Nitrogen in:
NH4NO3

Homework Equations


O=-2
H=+1

The Attempt at a Solution


N H4 N O3
+4 -6 = -2 to make it equal zero
then 2N=+2 hence N=+1

Or NH4=+1 then N=-3
NO3=-1 then N=+5
 
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Radwa Kamal said:
Or NH4=+1 then N=-3
NO3=-1 then N=+5

That's correct - these nitrogens are not equivalent and each has a different ON.

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