[Chemistry] Calculation of Pt potential

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SUMMARY

The potential of a platinum (Pt) electrode in a solution of 0.0263M K2PtCl4 and 0.1492M KCl is calculated using the Nernst Equation, E = Eo - 0.05912/2 * log Q. The expected answer is 0.78V. The discussion highlights the importance of considering the oxidation/reduction reactions involving Pt+2 and Cl2, as well as the presence of free Pt+2 ions in the solution, which may affect the calculated potential.

PREREQUISITES
  • Understanding of the Nernst Equation
  • Knowledge of electrochemical potential calculations
  • Familiarity with platinum complex ions
  • Basic concepts of oxidation and reduction reactions
NEXT STEPS
  • Study the Nernst Equation in detail, focusing on its application in electrochemistry
  • Research the behavior of platinum complex ions in solution
  • Explore the oxidation and reduction mechanisms of Cl2 and Pt+2
  • Investigate the impact of concentration on electrochemical potential
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Chemistry students, electrochemists, and anyone involved in studying electrochemical systems and potential calculations.

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Homework Statement



Calculate the potential of a Pt electrode immersed in a solution that is 0.0263M in K2PtCl4 and 0.1492M in KCl.
The answer given in 0.78

Homework Equations



E = Eo - 0.05912/2 * log Q (Nernst Equation)

The Attempt at a Solution



We try looking at the reduction of PtCl4 with oxidation of Cl2, and came out with an answer, but its different from the answer key given.

Maybe there is something with the oxidation/reduction of K?Thanks.
 
Last edited:
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And not Pt+2/Pt? This is solution of complexed Pt+2, it must contain some free Pt+2. Not much, but that's where I would start.
 

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