Suppose water at the bottom of a well contains dissolved methane. When the water is pumped up, the dissolved gas is released. How many moles of methane gas will be released if the well is 115 m deep and holds 2 L. Assume a Henry's law constant of 2.97 x 104 atm at 10o C (at the bottom of the well) and 4.13 x 104 atm at 25o C. The density of water is 1000 kg/m3. So we have: xmethane = ymethaneP/Hmethane(T) where y is the mol% and x is the mol fraction. We can find P for a column of water by using the relation P = ρgh where ρ = 1000 kg/m3, g = 9.8 m/s2, and h = 115 m. Thus P = 1.127 x 106 Pa = 8453 mmHg. I have Hmethane(10o C), but how do I obtain a value for ymethane so that I can plug it into the above equation to get the desired value for xmethane?