Circuit analysis complex numbers

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 1K views
x86
Gold Member
Messages
256
Reaction score
18

Homework Statement


Selection_027.png


I'm going crazy. I've done this problem nearly 20 times and keep getting the same answer. I've read my textbook so many times too! What am I doing wrong?

Homework Equations


Zcapacitor = 1/(jwC)
Zinductor = jwL
Zresistor = R

The Attempt at a Solution



Z for the capacitor -j1.667*10^3
Z for the inductor is j0.6

Z1 contains the capacitor and resistor on the righthand side of the circuit

Z1 = 2 - j1.667*10^3

Calculate Z12 (Z1 in parallel with the 22 ohm resistor)

1/Z12 = 1/22 + (2+j1.667*10^3)/(2.78*10^6)
Z12 =21.99-j2.903*10^-1

Z123 = Z12 in series with the inductor = 21.99 - j0.2903 + j0.6 = 21.99 + j0.309
 
Physics news on Phys.org
collinsmark said:
Don't forget to convert simple frequency f, which has units of Hz, to radial frequency ω, which has units of rad/sec.

Such a simple mistake on my part. Thanks.