Circuit Current: How to Calculate IA, IB, IC, ID

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SUMMARY

The discussion focuses on calculating the currents IA, IB, IC, and ID in a circuit powered by a voltage source, specifically with LED specifications of 50mA/2V. The user measured a current (ID) of approximately 180mA before the LEDs and seeks clarity on how to determine current at various points in the circuit. It is established that a circuit will draw current automatically based on the voltage specifications and potential differences, and that modeling the circuit with ideal components requires knowledge of equivalent impedances.

PREREQUISITES
  • Understanding of basic electrical concepts such as voltage, current, and resistance.
  • Familiarity with Ohm's Law and its application in circuit analysis.
  • Knowledge of LED specifications and their impact on circuit design.
  • Experience with circuit modeling and equivalent impedance calculations.
NEXT STEPS
  • Study how to apply Ohm's Law in various circuit configurations.
  • Learn about equivalent impedance in series and parallel circuits.
  • Research techniques for modeling real-life components as ideal components.
  • Explore methods for measuring current at different points in a circuit using multimeters.
USEFUL FOR

Electronics enthusiasts, electrical engineering students, and hobbyists looking to deepen their understanding of current calculations in circuits.

sandeep agari
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hello,
while making a circuit ( uploaded pic) ,the specifications of leds are 50mA/2V, i found the current ( ID )just before the leds to be around 180mA. i just want to know how to determine the currents in the circuit at various points( IA, IB , IC, ID). in general i want to know how to determine how a circuit draws current . do we have to take care of only voltage speciafications, voltage drops only and it will draw current automatically? just confused with the current calculations in this circuit. i hope if this will be cleared then it will help a lot in all others:) must respond.
 

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Welcome to PF;
The circuit powered from a voltage source will draw a current automatically (up to the limits of the equipment)... potential difference and current are related.
Typically you would model the real-life circuit as a circuit of ideal components - for this you need to know the equivalent impedences of the real components and how to model them as ideal components. How far you take it depends on how much detail you need.
 

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