The discussion focuses on calculating the current in a series circuit with three resistors, given a supply voltage (Vs) of 12V, a known resistor (R1) of 220 ohms, and voltage drops across R2 (7V) and R3 (2.5V). To find the current, one must first determine the total voltage drop across the resistors, which is 9.5V (7V + 2.5V). The current can then be calculated using Ohm's Law (I = V/R), where the total resistance is the sum of the known resistor and the equivalent resistance of the other two resistors.
PREREQUISITESElectrical engineering students, hobbyists working on circuit design, and anyone seeking to understand current calculations in series circuits.
blackout77 said:I need help finding the current in a series circuit with 3 resistors! I have Vs = 12V, R1 = 220ohms, at R2 has a voltage drop = 7V, and at R3 has a voltage drop = 2.5V. How do I find the current? I Know I have to add up all the resistors but how do I find the other 2 unknown resistors?