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Circuit Simplification, did I do this right?

  1. Oct 3, 2009 #1
    I have a circuit here:

    Circuit.jpg

    And I simplified it like so:

    simplifiedCircuit.jpg

    Did I do it correctly?

    Thanks,

    Jordan
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 3, 2009 #2

    lewando

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    Gold Member

    It looks right. Why are all components in ohms? That makes my head hurt.
     
  4. Oct 3, 2009 #3
    I'm glad it's right, The book tries to simplify things by adding the ohms to help us realize that impedance is similar to ohms when the book get's more complicated it shows the actual capacitance. So I guess the book is kind of in "Training Wheels" mode at the moment :)
     
  5. Oct 3, 2009 #4
    Oh and Quick question about Calculating Vb I know that I can use the Voltage Divider Rule to get it (I did that for Va)

    For Vb would I use the total impedance of all the impedances above the 820 ohms as say Z1 and then the impedance of the 820 Ohm resistor so it would be Vb=V* (820ohms/Z1+820Ohms) <-- VDR

    Is my thinking right?
     
  6. Oct 3, 2009 #5

    lewando

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    Gold Member

    Yes. But watch your parens: Vb = V * (820 / (z1 +820)), which is probably what you meant.
     
  7. Oct 3, 2009 #6
    Oh yeah your right, thanks for catching that.
     
  8. Oct 8, 2009 #7

    vk6kro

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    Science Advisor

    That isn't what they meant by simplifying the circuit, though.

    You just moved the components around on the page.

    You need to work out the combined impedances and the currents as asked for in the question.
     
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