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Homework Statement
Problem taken from : Fundamentals of Physics , Volume 2 ( 7th edition) Halliday , Resnick , Walker
In the figure, a 20.0V battery is connected across capacitors with capacitances C_{1}=C_{6}=3.00mF and
C_{3}=C_{5}=2.00C_{2}=2.00C_{4}=4.00mF
What is the equivalent capacitance C_{eq} of the capacitors?
Homework Equations
Capacitors in series:
Q = Q1 = Q2 = ...
V = v1 + v2 + ...
1/Ceq = 1/C1 + 1/C2 + ...
Capacitors in parallel:
Q = Q1 + Q2 + ...
V = V1 = V2 = ...
Ceq = C1 + C2 + ...
The Attempt at a Solution
Given data : C_{1}=C_{6}=3.00mF
C_{3}=C_{5}=4.00mF
C_{2}=C_{4}=2.00mF
I tried combining C_{3} and C_{5} since they were connected in series:
So 1/C_{35}= 1/4+1/4= C_{35}=2mF
Then I tried combining C_{35} and C_{4} as they were connected in parallel :
C_{345} = 2+2=4mF
Then I'm stuck on how to solve the network of C_{345},C_{1},C_{6} and C_{2}.
Did I do any of the above steps wrong and can anyone give me some hints on how to continue ?? Thanks !!
PS: I am sorry that the image in the pdf file may be quite small. Please magnify it to see the numbers .Thanks again !
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