Circuits: Draw Equivalent Resistance

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Homework Help Overview

The discussion revolves around simplifying a circuit to find the equivalent resistance, specifically focusing on the relationships between multiple resistors in series and parallel configurations. The original poster expresses confusion regarding the current flow and how to relate the resistances in the circuit.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the combination of resistors in parallel and series, questioning the understanding of current flow and the connections between resistors. There is an exploration of how to relate the remaining resistances in the circuit.

Discussion Status

Some participants provide guidance on combining resistors in parallel and series, while others seek clarification on the reasoning behind these combinations. Multiple interpretations of the circuit configuration are being explored, and there is an ongoing dialogue about the current's behavior in the circuit.

Contextual Notes

The original poster indicates uncertainty about the current's behavior in the circuit and how it affects the equivalent resistance calculations. There is an implication of homework constraints that may limit the depth of exploration.

Saladsamurai
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Homework Statement



Man, I stink at circuits. I have to simplify the 1st circuit in the image below to an equivalent resistance. I am almost there, but I am unsure of how to relate the remaining 3 resistances. In the drawing, a subscript Ri||j denotes the equivalent resistance of the two parallel resistors i and j; similarly, Ri+j is the equivalent resistance of the two series resistors i and j.

Now, I am not sure how to relate R_1,\,R_{(3||4)+5},\,R_2 and I think my confusion lies in the fact that I do not know what is going on with the current in this last circuit. Can someone help me out with that?

Screenshot2011-01-22at121832PM.png
 
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You have it pretty well finished! Just combine the R(3||4)+5 with the R2 in parallel. That result is in series with R1.
 
Delphi51 said:
You have it pretty well finished! Just combine the R(3||4)+5 with the R2 in parallel. That result is in series with R1.

OK! Now, this is because after the current leaves R1, it splits among R2 and R(3||4)+5 so we combine them in parallel. Right?

Thanks again Delphi!
 
They combine in parallel because they *are* in parallel! Look at how their leads connect.
 
gneill said:
They combine in parallel because they *are* in parallel! Look at how their leads connect.

Hi gneill! I don't understand your reply!
 
I think you are both saying the same thing! Parallel means both ends of the resistors are connected together AND that the current splits between them.
 

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