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[Circuits] Finding the Thevenin and Norton Equivalents #3
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[QUOTE="gneill, post: 4657028, member: 293536"] Not a mistake per se, not if you take it into account when you assign the polarity of the voltage. You are looking for the potential at terminal [B]a[/B] with respect to terminal [B]b[/B], so automatically that implies that the [B]a[/B] terminal is the where you'd put the + lead of your meter (if you were measuring it). You are driving the current into the [B]b[/B] terminal, so it becomes the "+" terminal for the resistance determination. That's contrary to the desired arrangement, and will result in a reversed sign for the voltage Vab. [/QUOTE]
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[Circuits] Finding the Thevenin and Norton Equivalents #3
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