- #1
Saladsamurai
- 3,020
- 7
Homework Statement
I am supposed to use mesh current analysis using the following circuit diagram which is in the phasor domain:
Homework Equations
KVL
The Attempt at a Solution
Let's number these meshes from left to right 1,2,3. Here is what confuses me:
If take a look at the 3rd mesh, wouldn't we just have the equation:
-(8 - 4j)*I2 + (8 - 4j)*I3 = 0
So I would naturally conclude that I2 and I3 are equal and opposite.
But I3= - 2e-30j is known. But if I use this logic, I get the wrong answer. I really suck at mesh, but when we had regular DC circuits, if there was a current source in a mesh, then we would just equate the mesh current to the source current. Is this different for AC? Or is my mistake somewhere else?