Mesh Analysis Method for Finding Current in a Circuit with Dependent Source

Click For Summary

Homework Help Overview

The discussion revolves around finding the current in each resistor within a circuit that includes a dependent source, utilizing the mesh analysis method. Participants are examining the application of Kirchhoff's Law and the relationships between the currents in the circuit loops.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to define the mesh currents and set up equations based on the mesh analysis method, but expresses uncertainty about the relationships between the currents and the dependent source. Participants question the labeling of circuit components and the definitions used for the currents, particularly how the dependent source relates to the loop currents.

Discussion Status

Participants are actively engaging in clarifying the setup of the problem, with some offering suggestions to visualize the circuit better. There is an ongoing exploration of how to correctly apply the mesh analysis method and the relationships between different currents in the circuit.

Contextual Notes

There are indications of confusion regarding the definitions of the dependent source and the relationship between the loop currents. The original poster has acknowledged previous mistakes and is seeking to correct them based on feedback from others.

Zack K
Messages
166
Reaction score
6

Homework Statement


Find the current in each resistor. (refer to uploaded diagram)

Homework Equations


##Kirchhoff's Law: I_s=I_1 + I_2##
Mesh analysis method

The Attempt at a Solution


I'm calling ##I_s## the total current before and after the current splitting up, and ##I_1## and ##I_2## are the mesh currents. Though I'm not sure if that's how it works.
Anyways, my setup:
I'll call the upper loop mesh 1 and the lower loop mesh 2
We have on dependent source, which is at ##R_3##, so I'll label the current there ##I_x##
$$mesh 1: -V_s+I_1R_1+I_1R_2+R_3(I_1-I_2)=0$$
$$mesh 2: -V_s+I_2R_4+R_3(I_2-I_1)+I_2R_5=0$$
$$Dependent Source: I_x=I_1-I_2$$
$$Kirchhoff's Law: I_s=I_1+I_2$$

I'm not entirely sure from here on. I could substitute each of these equations, but I don't see how it would let me solve for one variable, it would seem just as messy.
 

Attachments

  • Inked94ac9940-d104-4e73-8330-6ef522e5b9f8_LI.jpg
    Inked94ac9940-d104-4e73-8330-6ef522e5b9f8_LI.jpg
    20.1 KB · Views: 371
Last edited:
Physics news on Phys.org
For starters, can you label the resistors (in the diagram) R1 R2 etc. to assist following your equations?
Then can you put in an actual symbol for this dependent source. Is that Vs ? If so, how are Vs and Ix related? I don't follow how you get that I1 and I2 add to get Ix. Are I1 and I2 the loop currents?
 
scottdave said:
For starters, can you label the resistors (in the diagram) R1 R2 etc. to assist following your equations?
Sorry about that, I made a lot of clumsy mistakes. I uploaded a proper picture now.

scottdave said:
Then can you put in an actual symbol for this dependent source. Is that Vs ? If so, how are Vs and Ix related?
I defined Vs now as the potential from A to B.
scottdave said:
I don't follow how you get that I1 and I2 add to get Ix. Are I1 and I2 the loop currents?
Again, my bad. I modified it so ##I_x=I_1-I_2##, so it would be the sum of the currents.

If I made any other errors, then it would be form my misunderstanding of the problem/method. I just learned this form a wikipedia page since my professor gave us a very shaky lecture on it.
 
So the way you have defined it, the Vs ia not in either of the loops that you drew. Also look at the junction where Is and I1 meet. What is the current in R2 ?
 
scottdave said:
So the way you have defined it, the Vs ia not in either of the loops that you drew. Also look at the junction where Is and I1 meet. What is the current in R2 ?
I have no clue how I would get that. Circuits in parallel would have different currents, and that's what I'm trying to find using the mesh method.
 
Maybe it will help you if you draw a voltage source and hook it up to A and B to visualize what is going on in the circuit, and how you need to set up the equations. I still don't see where the dependent source is.
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
7
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
9K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K