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## Homework Statement

A tire 2.00 feet in diameter is placed on a balancing machine, where it is spun so that its tread is moving at a constant speed of 60.0 mi/h. A small stone is stuck in the tread of the tire. What is the acceleration of the stone as the tire is being balanced?

## Homework Equations

\omega = [tex]\frac{change in theta}{change in time}[/tex]

r = diameter/2

[tex]\alpha[/tex] = [tex]\frac{\omega - \omega_{0}} {time}[/tex]

a[tex]_{t}[/tex] = r*\alpha

## The Attempt at a Solution

[tex]\omega[/tex] = 840.3 rev/min = 88 radians/sec.

radius = .305m.

[tex]\alpha[/tex] = [tex]\frac{88 radians}{1 second}[/tex] = 88 radians/second[tex]^{2}[/tex].

a[tex]_{t}[/tex] = .305 *88 = 26.84 m/s[tex]^{2}[/tex]