Circular Motion and Static Friction

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SUMMARY

The discussion focuses on calculating the maximum speed of a metal cylinder on a rotating turntable, given a mass of 0.20 kg and a static friction coefficient of 0.08. The maximum frictional force is calculated as Fmax = 0.08 x 9.81 = 0.7848 N. The radial acceleration is determined using the formula Aradial = V^2/r, leading to a maximum speed of V = 0.767 m/s. A suggestion is made to simplify the problem by equating centripetal force to frictional force, which enhances problem-solving efficiency.

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Homework Statement




A small metal cylinder of mass m=0.20 kg sits on a rotating turntable. The coefficient of static friction between the metal cylinder and the turntable is us=.08. The cylinder is located 0.15m from the center of the turntable. Find the maximum speed that the cylinder can have without skidding. Acceleration due to gravity equal 9.81 m/s^2.



Homework Equations



F=MA
Fmax=us x normal force
Aradial=V^2/r

The Attempt at a Solution


Fmax=.08 x 9.81
Fmax=.7848

A=F/m
A=.7848/.2
A=3.94

Tangenitial acceleration equals zero so.

3.94=V^2/.15
V=.767 m/s

but i don't think this is correct. What am i doing wrong?

Any help is appreciated.
Thanks
 
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Likely you just forgot the mass when you did
Fmax=μmg = .08 x 9.81
Just a suggestion from an old timer - it is often helpful to separate the big picture from the details. I would begin this problem by writing the slipping condition:
Fc = Ff
then fill in the details with
m*v^2/r = μmg
cancel the m's and solve for v. Put in the numbers only in the last step. I can tell you that this kind of approach will serve you well when the problems get more complex.
 

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