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A 78.5kg man is about tocompletea bungee jump. If the bungee cord has a spring constant of 150 N/m, determine the period of oscillation that we will experience.

m= 78.5 Kg

k= 150 N/m

T=?

Relevant equations:

T= 2(pi)√(m/k)

The attempt at a solution

T= 2(pi)√(78.5kg/150 N/m)

I get, T=4.54s

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2nd Problem:

A 5.00 kg mass oscillates on a spring with a frequency of 0.667 Hz. Calculate the spring constant.

m= 5.00 Kg

f= 0.667 Hz

k= ?

Relevant equations:

T= 2(pi)√(m/k)

T=(1/f)

The attempt at a solution

T= (1/0.667Hz)

T= 1.499s

T= 2(pi)√(m/k)

I rearange and get:

k=87.84 N/m

If anyone can confirm or let me know if I did something wrong it would be great!

Thanks in advance!

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# Circular motion, grade 12 physics

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