Circular motion, grade 12 physics

  • #1
Problem:
A 78.5kg man is about tocompletea bungee jump. If the bungee cord has a spring constant of 150 N/m, determine the period of oscillation that we will experience.

m= 78.5 Kg
k= 150 N/m
T=?

Relevant equations:
T= 2(pi)√(m/k)

The attempt at a solution
T= 2(pi)√(78.5kg/150 N/m)
I get, T=4.54s

...............................................................................................................................
2nd Problem:
A 5.00 kg mass oscillates on a spring with a frequency of 0.667 Hz. Calculate the spring constant.

m= 5.00 Kg
f= 0.667 Hz
k= ?

Relevant equations:
T= 2(pi)√(m/k)
T=(1/f)


The attempt at a solution
T= (1/0.667Hz)
T= 1.499s
T= 2(pi)√(m/k)
I rearange and get:
k=87.84 N/m

If anyone can confirm or let me know if I did something wrong it would be great!
Thanks in advance!
 

Answers and Replies

  • #2
cepheid
Staff Emeritus
Science Advisor
Gold Member
5,192
38
It all looks okay to me!
 
  • #3
Thank you very much for looking over it!
 

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